Monday, November 3, 2025

The number of integrations in open-loop transfer function gives

 

59. For a second-order underdamped system, the peak overshoot MpM_p is given by:

a) eπζ/1ζ2e^{-\pi ζ / \sqrt{1-ζ^2}}
b) 1eζ1 - e^{-ζ}
c) eζπe^{-ζ \pi}
d) 1eπζ1 - e^{-πζ}
Answer: a) eπζ/1ζ2e^{-\pi ζ / \sqrt{1-ζ^2}}
Explanation: Overshoot depends exponentially on the damping ratio ζ.


60. The rise time trt_r for a second-order system is approximately:

a) 1.8ωn\frac{1.8}{ω_n}
b) 3ωn\frac{3}{ω_n}
c) 2.3ωn\frac{2.3}{ω_n}
d) 0.5ωn\frac{0.5}{ω_n}
Answer: a) 1.8ωn\frac{1.8}{ω_n}
Explanation: Approximate relation for 0–100% rise time in an underdamped system.


61. The term “bandwidth” of a control system refers to:

a) Frequency range of zero gain
b) Frequency range of unity phase
c) Frequency range over which system responds satisfactorily
d) Phase crossover frequency
Answer: c) Frequency range over which system responds satisfactorily
Explanation: Bandwidth is the frequency limit of significant response (typically -3 dB).


62. A proportional plus derivative (PD) controller improves:

a) Steady-state error
b) Transient response
c) Steady-state accuracy
d) None
Answer: b) Transient response
Explanation: Derivative term enhances damping, improving transient behavior.


63. The function of a tachogenerator in control systems is:

a) To measure displacement
b) To measure speed
c) To measure position
d) To amplify signal
Answer: b) To measure speed
Explanation: Tachogenerators produce voltage proportional to rotational speed.


64. The transfer function of a DC motor (armature control) is:

a) Ks(Ts+1)\frac{K}{s(Ts+1)}
b) KTs+1\frac{K}{Ts+1}
c) Ks2+sT+1\frac{K}{s^2 + sT + 1}
d) Ks2(Ts+1)\frac{K}{s^2(Ts+1)}
Answer: a) Ks(Ts+1)\frac{K}{s(Ts+1)}
Explanation: One integration from speed to position, and one lag due to motor time constant.


65. The error detector in an automatic control system compares:

a) Output and input
b) Feedback and reference
c) Desired output and actual output
d) All of these
Answer: d) All of these
Explanation: Error is difference between desired (reference) and actual (feedback) signals.


66. The transfer function of a second-order system is:

ωn2s2+2ζωns+ωn2\frac{ω_n^2}{s^2 + 2ζω_n s + ω_n^2}.
Its natural frequency is:
a) ζωnζω_n
b) ωnω_n
c) 2ζωn2ζω_n
d) ωn2ω_n^2
Answer: b) ωnω_n
Explanation: ωnω_n represents natural frequency of oscillation.


67. The steady-state error for a unit parabolic input is zero for:

a) Type 0
b) Type 1
c) Type 2
d) None
Answer: c) Type 2
Explanation: Two integrators eliminate error for parabolic input.


68. The open-loop poles determine:

a) Static error
b) Dynamic response
c) Gain margin
d) Phase margin
Answer: b) Dynamic response
Explanation: Pole locations dictate system speed and oscillation characteristics.


69. The characteristic equation of a unity feedback system is:

a) 1+G(s)=01 + G(s) = 0
b) 1+G(s)H(s)=01 + G(s)H(s) = 0
c) G(s)=0G(s) = 0
d) H(s)=0H(s) = 0
Answer: b) 1+G(s)H(s)=01 + G(s)H(s) = 0
Explanation: Derived from closed-loop transfer function denominator.


70. The steady-state error constants are:

a) Kp,Kv,KaK_p, K_v, K_a
b) Kd,Ki,KpK_d, K_i, K_p
c) K1,K2,K3K_1, K_2, K_3
d) None
Answer: a) Kp,Kv,KaK_p, K_v, K_a
Explanation: They correspond to step, ramp, and parabolic input errors respectively.


71. The Nyquist plot of a Type 1 system passes through:

a) Origin
b) (-1,0)
c) (1,0)
d) (0,1)
Answer: a) Origin
Explanation: Type 1 (one integrator) introduces -90° phase lag at low frequencies, passing through origin.


72. The main advantage of state-space over transfer function is:

a) Easier Laplace computation
b) Handles MIMO systems
c) Requires fewer equations
d) None
Answer: b) Handles MIMO systems
Explanation: State-space can describe multi-input, multi-output systems directly.


73. The transient response of a second-order system is primarily determined by:

a) Zeros
b) Damping ratio and natural frequency
c) Gain
d) Feedback
Answer: b) Damping ratio and natural frequency
Explanation: ζ and ωₙ define rise time, overshoot, and settling time.


74. A system with characteristic equation s2+6s+25=0s^2 + 6s + 25 = 0 is:

a) Overdamped
b) Underdamped
c) Critically damped
d) Unstable
Answer: b) Underdamped
Explanation: ζ=6/(225)=0.6<1ζ = 6 / (2√25) = 0.6 < 1 → underdamped.


75. A phase lead compensator improves:

a) Stability margin
b) Steady-state error
c) Low-frequency response
d) All
Answer: a) Stability margin
Explanation: Lead compensators add positive phase → improved phase margin.


76. The polar plot of a first-order system is a:

a) Circle
b) Straight line
c) Parabola
d) Spiral
Answer: a) Circle
Explanation: For G(jω)=11+jωTG(jω) = \frac{1}{1+jωT}, the locus is a circle in complex plane.


77. The Bode magnitude of 1s\frac{1}{s} is:

a) +20 dB/dec
b) -20 dB/dec
c) 0 dB
d) None
Answer: b) -20 dB/dec
Explanation: Integrator causes -20 dB per decade slope.


78. For stability using Routh-Hurwitz, all elements of the first column must be:

a) Positive
b) Negative
c) Alternate sign
d) Zero
Answer: a) Positive
Explanation: All positive → no sign changes → all poles in LHP.


79. If any row of Routh array becomes zero, the system has:

a) Imaginary roots
b) Repeated real roots
c) Complex roots
d) None
Answer: a) Imaginary roots
Explanation: Zero row indicates symmetric root pairs on imaginary axis → marginal stability.


80. The condition for controllability is:

a) Rank [B AB A²B … Aⁿ⁻¹B] = n
b) det(A) ≠ 0
c) All poles distinct
d) Trace(A) ≠ 0
Answer: a) Rank [B AB A²B … Aⁿ⁻¹B] = n
Explanation: Kalman controllability criterion.


81. For observability, the matrix used is:

a) [C; CA; CA²; …; CAⁿ⁻¹]
b) [B AB …]
c) [A B C D]
d) [A C D]
Answer: a) [C; CA; CA²; …; CAⁿ⁻¹]
Explanation: Kalman observability test.


82. The open-loop transfer function K(s+3)s(s+2)(s+5)\frac{K(s+3)}{s(s+2)(s+5)} has how many asymptotes?

a) 1
b) 2
c) 3
d) None
Answer: b) 2
Explanation: 3 poles − 1 zero = 2 asymptotes.


83. For the same system, centroid of asymptotes =

(25+0)(3)2\frac{(-2-5+0)-(−3)}{2} = ?
a) -2
b) -1
c) -2
d) -2
Answer: a) -2
Explanation: Centroid = (sum of poles − sum of zeros)/(p−z) = (-7+3)/2 = -2.


84. When feedback gain is increased:

a) Stability increases
b) Bandwidth increases
c) Sensitivity increases
d) Gain margin increases
Answer: b) Bandwidth increases
Explanation: Higher feedback improves response speed but may reduce stability.


85. The number of encirclements in Nyquist plot equals:

a) Number of open-loop poles in LHP
b) Number of closed-loop poles in RHP
c) Difference between right-half open and closed-loop poles
d) None
Answer: c) Difference between right-half open and closed-loop poles
Explanation: N=ZPN = Z - P, where N = encirclements, Z = RHP closed-loop poles, P = RHP open-loop poles.


86. Servo systems are primarily used for:

a) Speed control
b) Position control
c) Current control
d) Temperature control
Answer: b) Position control
Explanation: Servo systems precisely control angular/linear position.


87. A stepper motor is used in control systems for:

a) Continuous control
b) Discrete position control
c) Speed control
d) None
Answer: b) Discrete position control
Explanation: Stepper moves in fixed angular steps → discrete control.


88. In frequency response, the phase lag increases with:

a) Frequency
b) Gain
c) Damping ratio
d) Time constant decrease
Answer: a) Frequency
Explanation: Lag increases as system’s phase angle drops at higher frequencies.


89. The final value theorem is used to find:

a) Initial value
b) Steady-state value
c) Transient response
d) Time constant
Answer: b) Steady-state value
Explanation: limtf(t)=lims0sF(s)\lim_{t→∞} f(t) = \lim_{s→0} sF(s).


90. The initial value theorem is used to find:

a) Steady-state response
b) Starting value of response
c) Average value
d) None
Answer: b) Starting value of response
Explanation: limt0f(t)=limssF(s)\lim_{t→0} f(t) = \lim_{s→∞} sF(s).


91. In a unity feedback system, steady-state error for step input is given by:

a) 1/(1+Kp)1/(1+K_p)
b) 1/Kp1/K_p
c) Kp/(1+Kp)K_p/(1+K_p)
d) 1+Kp1+K_p
Answer: a) 1/(1+Kp)1/(1+K_p)
Explanation: Derived from position error constant Kp=lims0G(s)K_p = \lim_{s→0} G(s).


92. If damping ratio ζ = 1, the system is:

a) Overdamped
b) Underdamped
c) Critically damped
d) Unstable
Answer: c) Critically damped
Explanation: ζ = 1 → fastest response without oscillation.


93. For a second-order system, the damping ratio ζ = 0 gives:

a) Overdamped
b) Critically damped
c) Undamped
d) Oscillatory stable
Answer: c) Undamped
Explanation: ζ = 0 → no damping → continuous oscillations.


94. A unity feedback system has G(s)=10s(s+2)G(s) = \frac{10}{s(s+2)}. Find KvK_v.

Answer: Kv=lims0sG(s)=102=5K_v = \lim_{s→0} sG(s) = \frac{10}{2} = 5
Explanation: Velocity constant for Type 1 system.


95. The steady-state error for ramp input is ess=1Kve_{ss} = \frac{1}{K_v}. For Kv=5K_v = 5:

a) 0.2
b) 5
c) 0.1
d) 1
Answer: a) 0.2
Explanation: ess=1/5=0.2e_{ss} = 1/5 = 0.2.


96. The phase margin of 45° gives:

a) Highly stable system
b) Marginally stable
c) Satisfactory stability
d) Unstable
Answer: c) Satisfactory stability
Explanation: Phase margin between 30–60° → good transient response.


97. The gain margin of 10 dB means:

a) Gain can be increased 10 times before instability
b) Gain can increase by factor ≈ 3.16
c) Gain can increase by 10%
d) Gain decreases 10×
Answer: b) Gain can increase by factor ≈ 3.16
Explanation: 10 dB = 20 log₁₀(K) → K ≈ 3.16.


98. The number of integrations in open-loop transfer function gives:

a) Order
b) Type
c) Damping
d) Gain
Answer: b) Type
Explanation: Type equals number of integrators (poles at origin).


99. A system with gain margin = 0 dB and phase margin = 0° is:

a) Stable
b) Unstable
c) Marginally stable
d) Highly stable
Answer: c) Marginally stable
Explanation: Both zero margins → on stability boundary.


100. Increasing derivative gain KdK_d:

a) Increases overshoot
b) Reduces overshoot
c) No effect
d) Increases rise time
Answer: b) Reduces overshoot
Explanation: Derivative action adds damping → reduces oscillation.

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